36=7(y+2)+4y

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Solution for 36=7(y+2)+4y equation: 



36=7(y+2)+4y

We move all terms to the left:

36-(7(y+2)+4y)=0



We calculate terms in parentheses: -(7(y+2)+4y), so:

7(y+2)+4y

We add all the numbers together, and all the variables

4y+7(y+2)

We multiply parentheses

4y+7y+14

We add all the numbers together, and all the variables

11y+14

Back to the equation:

-(11y+14)



We get rid of parentheses

-11y-14+36=0

We add all the numbers together, and all the variables

-11y+22=0

We move all terms containing y to the left, all other terms to the right

-11y=-22

y=-22/-11

y=+2

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