5+2(3x-5)=5-5(2x+1)

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Solution for 5+2(3x-5)=5-5(2x+1) equation: 



5+2(3x-5)=5-5(2x+1)

We move all terms to the left:

5+2(3x-5)-(5-5(2x+1))=0

We multiply parentheses

6x-(5-5(2x+1))-10+5=0



We calculate terms in parentheses: -(5-5(2x+1)), so:

5-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+5

We multiply parentheses

-10x-5+5

We add all the numbers together, and all the variables

-10x

Back to the equation:

-(-10x)



We add all the numbers together, and all the variables

6x-(-10x)-5=0

We get rid of parentheses

6x+10x-5=0

We add all the numbers together, and all the variables

16x-5=0

We move all terms containing x to the left, all other terms to the right

16x=5

x=5/16

x=5/16

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