6(x+3)+4=8x-2(x-4)

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Solution for 6(x+3)+4=8x-2(x-4) equation: 



6(x+3)+4=8x-2(x-4)

We move all terms to the left:

6(x+3)+4-(8x-2(x-4))=0

We multiply parentheses

6x-(8x-2(x-4))+18+4=0



We calculate terms in parentheses: -(8x-2(x-4)), so:

8x-2(x-4)

We multiply parentheses

8x-2x+8

We add all the numbers together, and all the variables

6x+8

Back to the equation:

-(6x+8)



We add all the numbers together, and all the variables

6x-(6x+8)+22=0

We get rid of parentheses

6x-6x-8+22=0

We add all the numbers together, and all the variables

14!=0

There is no solution for this equation

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