36=3(2x+1)+3

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Solution for 36=3(2x+1)+3 equation:



36=3(2x+1)+3
We move all terms to the left:
36-(3(2x+1)+3)=0
We calculate terms in parentheses: -(3(2x+1)+3), so:
3(2x+1)+3
We multiply parentheses
6x+3+3
We add all the numbers together, and all the variables
6x+6
Back to the equation:
-(6x+6)
We get rid of parentheses
-6x-6+36=0
We add all the numbers together, and all the variables
-6x+30=0
We move all terms containing x to the left, all other terms to the right
-6x=-30
x=-30/-6
x=+5

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