2(2x-8+2x)=56

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Solution for 2(2x-8+2x)=56 equation: 



2(2x-8+2x)=56

We move all terms to the left:

2(2x-8+2x)-(56)=0

We add all the numbers together, and all the variables

2(4x-8)-56=0

We multiply parentheses

8x-16-56=0

We add all the numbers together, and all the variables

8x-72=0

We move all terms containing x to the left, all other terms to the right

8x=72

x=72/8

x=9

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