3(x+1)=7(x-3-2

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Solution for 3(x+1)=7(x-3-2 equation: 



3(x+1)=7(x-3-2

We move all terms to the left:

3(x+1)-(7(x-3-2)=0

We add all the numbers together, and all the variables

3(x+1)-(7(x-5)=0

We multiply parentheses

3x-(7(x-5)+3=0

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