360=(3x+30)2x

Solution for 360=(3x+30)2x equation:

360=(3x+30)2x

We move all terms to the left:

360-((3x+30)2x)=0


We calculate terms in parentheses: -((3x+30)2x), so:

(3x+30)2x

We multiply parentheses

6x^2+60x

Back to the equation:

-(6x^2+60x)


We get rid of parentheses

-6x^2-60x+360=0

a = -6; b = -60; c = +360;
Δ = b2-4ac
Δ = -602-4·(-6)·360
Δ = 12240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12240}=\sqrt{144*85}=\sqrt{144}*\sqrt{85}=12\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-12\sqrt{85}}{2*-6}=\frac{60-12\sqrt{85}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+12\sqrt{85}}{2*-6}=\frac{60+12\sqrt{85}}{-12}
$