-3(2y-2)-y=-2(y-5)

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Solution for -3(2y-2)-y=-2(y-5) equation: 



-3(2y-2)-y=-2(y-5)

We move all terms to the left:

-3(2y-2)-y-(-2(y-5))=0

We add all the numbers together, and all the variables

-1y-3(2y-2)-(-2(y-5))=0

We multiply parentheses

-1y-6y-(-2(y-5))+6=0



We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We add all the numbers together, and all the variables

-7y-(-2y+10)+6=0

We get rid of parentheses

-7y+2y-10+6=0

We add all the numbers together, and all the variables

-5y-4=0

We move all terms containing y to the left, all other terms to the right

-5y=4

y=4/-5

y=-4/5

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