36-(3c+4)=2(c+4)+6

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Solution for 36-(3c+4)=2(c+4)+6 equation:


Simplifying
36 + -1(3c + 4) = 2(c + 4) + 6

Reorder the terms:
36 + -1(4 + 3c) = 2(c + 4) + 6
36 + (4 * -1 + 3c * -1) = 2(c + 4) + 6
36 + (-4 + -3c) = 2(c + 4) + 6

Combine like terms: 36 + -4 = 32
32 + -3c = 2(c + 4) + 6

Reorder the terms:
32 + -3c = 2(4 + c) + 6
32 + -3c = (4 * 2 + c * 2) + 6
32 + -3c = (8 + 2c) + 6

Reorder the terms:
32 + -3c = 8 + 6 + 2c

Combine like terms: 8 + 6 = 14
32 + -3c = 14 + 2c

Solving
32 + -3c = 14 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
32 + -3c + -2c = 14 + 2c + -2c

Combine like terms: -3c + -2c = -5c
32 + -5c = 14 + 2c + -2c

Combine like terms: 2c + -2c = 0
32 + -5c = 14 + 0
32 + -5c = 14

Add '-32' to each side of the equation.
32 + -32 + -5c = 14 + -32

Combine like terms: 32 + -32 = 0
0 + -5c = 14 + -32
-5c = 14 + -32

Combine like terms: 14 + -32 = -18
-5c = -18

Divide each side by '-5'.
c = 3.6

Simplifying
c = 3.6

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