(2+2j)x(2-2j)=

Solution for (2+2j)x(2-2j)= equation:

Simplifying
(2 + 2j) * x(2 + -2j) = 0

Reorder the terms for easier multiplication:
x(2 + 2j)(2 + -2j) = 0

Multiply (2 + 2j) * (2 + -2j)
x(2(2 + -2j) + 2j * (2 + -2j)) = 0
x((2 * 2 + -2j * 2) + 2j * (2 + -2j)) = 0
x((4 + -4j) + 2j * (2 + -2j)) = 0
x(4 + -4j + (2 * 2j + -2j * 2j)) = 0
x(4 + -4j + (4j + -4j2)) = 0

Combine like terms: -4j + 4j = 0
x(4 + 0 + -4j2) = 0
x(4 + -4j2) = 0
(4 * x + -4j2 * x) = 0

Reorder the terms:
(-4j2x + 4x) = 0
(-4j2x + 4x) = 0

Solving
-4j2x + 4x = 0

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4x' to each side of the equation.
-4j2x + 4x + -4x = 0 + -4x

Combine like terms: 4x + -4x = 0
-4j2x + 0 = 0 + -4x
-4j2x = 0 + -4x
Remove the zero:
-4j2x = -4x

Divide each side by '-4x'.
j2 = 1

Simplifying
j2 = 1

Take the square root of each side:
j = {-1, 1}