If it's not what You are looking for type in the equation solver your own equation and let us solve it.
35r^2+3r-2=0
a = 35; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·35·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-17}{2*35}=\frac{-20}{70} =-2/7 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+17}{2*35}=\frac{14}{70} =1/5 $
| 5x+150+3x+6=180 | | 34+0.50x=20+0.75 | | b2-12b+29=-3 | | 3.5a+6=18-2.5a | | x-2.26=9.1 | | -0.5y+20-0.5y=12 | | 18+b+41=9b+3 | | 7x5=35 | | .50=x/2.5*100 | | 3-4y=y+18 | | 38=19-x | | ((7)/(5x))+((3)/(x))=((4)/(x-4)) | | G=2p-17 | | 2f^2-50=0 | | P(a)=0.54 | | 5x-8=98 | | 93x7=651 | | -3p+-12=0 | | n/3+-14=-17 | | 6y+4=9y+10 | | 17a+5=19a-1 | | 19z=z+18 | | 3b=4b-20 | | c=2c-19 | | 4u=6u-30 | | 3x-12x=211 | | 18n40=22n | | 3v=4v-19 | | 7(x+5)=3x-6 | | 7(x-2)-5=3(x-1) | | C=17x+3 | | (12x+19)+(8x+11)=180 |