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((7)/(5x))+((3)/(x))=((4)/(x-4))
We move all terms to the left:
((7)/(5x))+((3)/(x))-(((4)/(x-4)))=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: (x-4)))!=0We add all the numbers together, and all the variables
x∈R
(+7/5x)+(+3/x)-((4/(x-4)))=0
We get rid of parentheses
7/5x+3/x-((4/(x-4)))=0
We calculate fractions
We do not support expression: x^3
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