35=6(y+4)+5y

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Solution for 35=6(y+4)+5y equation: 



35=6(y+4)+5y

We move all terms to the left:

35-(6(y+4)+5y)=0



We calculate terms in parentheses: -(6(y+4)+5y), so:

6(y+4)+5y

We add all the numbers together, and all the variables

5y+6(y+4)

We multiply parentheses

5y+6y+24

We add all the numbers together, and all the variables

11y+24

Back to the equation:

-(11y+24)



We get rid of parentheses

-11y-24+35=0

We add all the numbers together, and all the variables

-11y+11=0

We move all terms containing y to the left, all other terms to the right

-11y=-11

y=-11/-11

y=1

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