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5(5-x)=2x+4(x-1)
We move all terms to the left:
5(5-x)-(2x+4(x-1))=0
We add all the numbers together, and all the variables
5(-1x+5)-(2x+4(x-1))=0
We multiply parentheses
-5x-(2x+4(x-1))+25=0
We calculate terms in parentheses: -(2x+4(x-1)), so:We get rid of parentheses
2x+4(x-1)
We multiply parentheses
2x+4x-4
We add all the numbers together, and all the variables
6x-4
Back to the equation:
-(6x-4)
-5x-6x+4+25=0
We add all the numbers together, and all the variables
-11x+29=0
We move all terms containing x to the left, all other terms to the right
-11x=-29
x=-29/-11
x=2+7/11
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