-22=4(1+d)+6

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Solution for -22=4(1+d)+6 equation: 



-22=4(1+d)+6

We move all terms to the left:

-22-(4(1+d)+6)=0

We add all the numbers together, and all the variables

-(4(d+1)+6)-22=0



We calculate terms in parentheses: -(4(d+1)+6), so:

4(d+1)+6

We multiply parentheses

4d+4+6

We add all the numbers together, and all the variables

4d+10

Back to the equation:

-(4d+10)



We get rid of parentheses

-4d-10-22=0

We add all the numbers together, and all the variables

-4d-32=0

We move all terms containing d to the left, all other terms to the right

-4d=32

d=32/-4

d=-8

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