35=4(y+2)-7y

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Solution for 35=4(y+2)-7y equation: 



35=4(y+2)-7y

We move all terms to the left:

35-(4(y+2)-7y)=0



We calculate terms in parentheses: -(4(y+2)-7y), so:

4(y+2)-7y

We add all the numbers together, and all the variables

-7y+4(y+2)

We multiply parentheses

-7y+4y+8

We add all the numbers together, and all the variables

-3y+8

Back to the equation:

-(-3y+8)



We get rid of parentheses

3y-8+35=0

We add all the numbers together, and all the variables

3y+27=0

We move all terms containing y to the left, all other terms to the right

3y=-27

y=-27/3

y=-9

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