4(n+3)=2(n+1)

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Solution for 4(n+3)=2(n+1) equation: 



4(n+3)=2(n+1)

We move all terms to the left:

4(n+3)-(2(n+1))=0

We multiply parentheses

4n-(2(n+1))+12=0



We calculate terms in parentheses: -(2(n+1)), so:

2(n+1)

We multiply parentheses

2n+2

Back to the equation:

-(2n+2)



We get rid of parentheses

4n-2n-2+12=0

We add all the numbers together, and all the variables

2n+10=0

We move all terms containing n to the left, all other terms to the right

2n=-10

n=-10/2

n=-5

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