2b+2(b-10)=80

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Solution for 2b+2(b-10)=80 equation: 



2b+2(b-10)=80

We move all terms to the left:

2b+2(b-10)-(80)=0

We multiply parentheses

2b+2b-20-80=0

We add all the numbers together, and all the variables

4b-100=0

We move all terms containing b to the left, all other terms to the right

4b=100

b=100/4

b=25

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