-3(1+2b)=-(3+4b)

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Solution for -3(1+2b)=-(3+4b) equation: 



-3(1+2b)=-(3+4b)

We move all terms to the left:

-3(1+2b)-(-(3+4b))=0

We add all the numbers together, and all the variables

-3(2b+1)-(-(4b+3))=0

We multiply parentheses

-6b-(-(4b+3))-3=0



We calculate terms in parentheses: -(-(4b+3)), so:

-(4b+3)

We get rid of parentheses

-4b-3

Back to the equation:

-(-4b-3)



We get rid of parentheses

-6b+4b+3-3=0

We add all the numbers together, and all the variables

-2b=0

b=0/-2

b=0

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