35+5a=3(4a+1)-3a

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Solution for 35+5a=3(4a+1)-3a equation: 



35+5a=3(4a+1)-3a

We move all terms to the left:

35+5a-(3(4a+1)-3a)=0



We calculate terms in parentheses: -(3(4a+1)-3a), so:

3(4a+1)-3a

We add all the numbers together, and all the variables

-3a+3(4a+1)

We multiply parentheses

-3a+12a+3

We add all the numbers together, and all the variables

9a+3

Back to the equation:

-(9a+3)



We get rid of parentheses

5a-9a-3+35=0

We add all the numbers together, and all the variables

-4a+32=0

We move all terms containing a to the left, all other terms to the right

-4a=-32

a=-32/-4

a=+8

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