-2(-8-5v)+12v-5=11(1+2v)

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Solution for -2(-8-5v)+12v-5=11(1+2v) equation: 



-2(-8-5v)+12v-5=11(1+2v)

We move all terms to the left:

-2(-8-5v)+12v-5-(11(1+2v))=0

We add all the numbers together, and all the variables

-2(-5v-8)+12v-(11(2v+1))-5=0

We add all the numbers together, and all the variables

12v-2(-5v-8)-(11(2v+1))-5=0

We multiply parentheses

12v+10v-(11(2v+1))+16-5=0



We calculate terms in parentheses: -(11(2v+1)), so:

11(2v+1)

We multiply parentheses

22v+11

Back to the equation:

-(22v+11)



We add all the numbers together, and all the variables

22v-(22v+11)+11=0

We get rid of parentheses

22v-22v-11+11=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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