34/6=9(2x+1)/3

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Solution for 34/6=9(2x+1)/3 equation: 



34/6=9(2x+1)/3

We move all terms to the left:

34/6-(9(2x+1)/3)=0

We calculate fractions


(-(9(2x+1)*6)/()+()/()=0



We calculate terms in parentheses: +(-(9(2x+1)*6)/()+()/(), so:

-(9(2x+1)*6)/()+()/(

We add all the numbers together, and all the variables

-(9(2x+1)*6)/()+1

We multiply all the terms by the denominator


-(9(2x+1)*6)+1*()



We calculate terms in parentheses: -(9(2x+1)*6), so:

9(2x+1)*6

We multiply parentheses

108x+54

Back to the equation:

-(108x+54)



We add all the numbers together, and all the variables

-(108x+54)

We get rid of parentheses

-108x-54

Back to the equation:

+(-108x-54)



We get rid of parentheses

-108x-54=0

We move all terms containing x to the left, all other terms to the right

-108x=54

x=54/-108

x=-1/2

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