2(10-x)=12-10(11+12x)

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Solution for 2(10-x)=12-10(11+12x) equation:



2(10-x)=12-10(11+12x)
We move all terms to the left:
2(10-x)-(12-10(11+12x))=0
We add all the numbers together, and all the variables
2(-1x+10)-(12-10(12x+11))=0
We multiply parentheses
-2x-(12-10(12x+11))+20=0
We calculate terms in parentheses: -(12-10(12x+11)), so:
12-10(12x+11)
determiningTheFunctionDomain -10(12x+11)+12
We multiply parentheses
-120x-110+12
We add all the numbers together, and all the variables
-120x-98
Back to the equation:
-(-120x-98)
We get rid of parentheses
-2x+120x+98+20=0
We add all the numbers together, and all the variables
118x+118=0
We move all terms containing x to the left, all other terms to the right
118x=-118
x=-118/118
x=-1

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