(2x+3)(3x+9)=0

Solution for (2x+3)(3x+9)=0 equation:

(2x+3)(3x+9)=0

We multiply parentheses ..

(+6x^2+18x+9x+27)=0

We get rid of parentheses

6x^2+18x+9x+27=0

We add all the numbers together, and all the variables

6x^2+27x+27=0

a = 6; b = 27; c = +27;
Δ = b2-4ac
Δ = 272-4·6·27
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-9}{2*6}=\frac{-36}{12}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+9}{2*6}=\frac{-18}{12}
=-1+1/2
$