32=-3(7z-2)

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Solution for 32=-3(7z-2) equation: 



32=-3(7z-2)

We move all terms to the left:

32-(-3(7z-2))=0



We calculate terms in parentheses: -(-3(7z-2)), so:

-3(7z-2)

We multiply parentheses

-21z+6

Back to the equation:

-(-21z+6)



We get rid of parentheses

21z-6+32=0

We add all the numbers together, and all the variables

21z+26=0

We move all terms containing z to the left, all other terms to the right

21z=-26

z=-26/21

z=-1+5/21

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