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32-(x+6)=19+(2x+1)
We move all terms to the left:
32-(x+6)-(19+(2x+1))=0
We get rid of parentheses
-x-(19+(2x+1))-6+32=0
We calculate terms in parentheses: -(19+(2x+1)), so:We add all the numbers together, and all the variables
19+(2x+1)
determiningTheFunctionDomain (2x+1)+19
We get rid of parentheses
2x+1+19
We add all the numbers together, and all the variables
2x+20
Back to the equation:
-(2x+20)
-1x-(2x+20)+26=0
We get rid of parentheses
-1x-2x-20+26=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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