32+3y-12=14y-10-5y

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Solution for 32+3y-12=14y-10-5y equation: 



32+3y-12=14y-10-5y

We move all terms to the left:

32+3y-12-(14y-10-5y)=0

We add all the numbers together, and all the variables

3y-(9y-10)+32-12=0

We add all the numbers together, and all the variables

3y-(9y-10)+20=0

We get rid of parentheses

3y-9y+10+20=0

We add all the numbers together, and all the variables

-6y+30=0

We move all terms containing y to the left, all other terms to the right

-6y=-30

y=-30/-6

y=+5

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