9-(2-3t)=6+2t-(5+t)

Solution for 9-(2-3t)=6+2t-(5+t) equation:

9-(2-3t)=6+2t-(5+t)

We move all terms to the left:

9-(2-3t)-(6+2t-(5+t))=0

We add all the numbers together, and all the variables

-(-3t+2)-(6+2t-(t+5))+9=0

We get rid of parentheses

3t-(6+2t-(t+5))-2+9=0


We calculate terms in parentheses: -(6+2t-(t+5)), so:

6+2t-(t+5)

determiningTheFunctionDomain
2t-(t+5)+6

We get rid of parentheses

2t-t-5+6

We add all the numbers together, and all the variables

t+1

Back to the equation:

-(t+1)


We add all the numbers together, and all the variables

3t-(t+1)+7=0

We get rid of parentheses

3t-t-1+7=0

We add all the numbers together, and all the variables

2t+6=0

We move all terms containing t to the left, all other terms to the right

2t=-6

t=-6/2

t=-3