-2(z-1)+3=-3z+(z-1)

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Solution for -2(z-1)+3=-3z+(z-1) equation: 



-2(z-1)+3=-3z+(z-1)

We move all terms to the left:

-2(z-1)+3-(-3z+(z-1))=0

We multiply parentheses

-2z-(-3z+(z-1))+2+3=0



We calculate terms in parentheses: -(-3z+(z-1)), so:

-3z+(z-1)

We get rid of parentheses

-3z+z-1

We add all the numbers together, and all the variables

-2z-1

Back to the equation:

-(-2z-1)



We add all the numbers together, and all the variables

-2z-(-2z-1)+5=0

We get rid of parentheses

-2z+2z+1+5=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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