32(2x-3)=6+x

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Solution for 32(2x-3)=6+x equation: 



32(2x-3)=6+x

We move all terms to the left:

32(2x-3)-(6+x)=0

We add all the numbers together, and all the variables

32(2x-3)-(x+6)=0

We multiply parentheses

64x-(x+6)-96=0

We get rid of parentheses

64x-x-6-96=0

We add all the numbers together, and all the variables

63x-102=0

We move all terms containing x to the left, all other terms to the right

63x=102

x=102/63

x=1+13/21

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