-5(1+4b)=-b+2(-8b+5)

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Solution for -5(1+4b)=-b+2(-8b+5) equation: 



-5(1+4b)=-b+2(-8b+5)

We move all terms to the left:

-5(1+4b)-(-b+2(-8b+5))=0

We add all the numbers together, and all the variables

-5(4b+1)-(-b+2(-8b+5))=0

We multiply parentheses

-20b-(-b+2(-8b+5))-5=0



We calculate terms in parentheses: -(-b+2(-8b+5)), so:

-b+2(-8b+5)

We add all the numbers together, and all the variables

-1b+2(-8b+5)

We multiply parentheses

-1b-16b+10

We add all the numbers together, and all the variables

-17b+10

Back to the equation:

-(-17b+10)



We get rid of parentheses

-20b+17b-10-5=0

We add all the numbers together, and all the variables

-3b-15=0

We move all terms containing b to the left, all other terms to the right

-3b=15

b=15/-3

b=-5

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