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3/x+9/2x=1
We move all terms to the left:
3/x+9/2x-(1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We calculate fractions
x!=0/2
x!=0
x∈R
6x/2x^2+9x/2x^2-1=0
We multiply all the terms by the denominator
6x+9x-1*2x^2=0
We add all the numbers together, and all the variables
15x-1*2x^2=0
Wy multiply elements
-2x^2+15x=0
a = -2; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-2)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-2}=\frac{-30}{-4} =7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-2}=\frac{0}{-4} =0 $
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