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24x-8=x2
We move all terms to the left:
24x-8-(x2)=0
We add all the numbers together, and all the variables
-1x^2+24x-8=0
a = -1; b = 24; c = -8;
Δ = b2-4ac
Δ = 242-4·(-1)·(-8)
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{34}}{2*-1}=\frac{-24-4\sqrt{34}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{34}}{2*-1}=\frac{-24+4\sqrt{34}}{-2} $
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