2(2n-2)=3(n+3)

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Solution for 2(2n-2)=3(n+3) equation: 



2(2n-2)=3(n+3)

We move all terms to the left:

2(2n-2)-(3(n+3))=0

We multiply parentheses

4n-(3(n+3))-4=0



We calculate terms in parentheses: -(3(n+3)), so:

3(n+3)

We multiply parentheses

3n+9

Back to the equation:

-(3n+9)



We get rid of parentheses

4n-3n-9-4=0

We add all the numbers together, and all the variables

n-13=0

We move all terms containing n to the left, all other terms to the right

n=13

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