(.3x-0.1)(0.05x-1)=0

Solution for (.3x-0.1)(0.05x-1)=0 equation:

(.3x-0.1)(0.05x-1)=0

We multiply parentheses ..

(+0x^2-1x-0x+0.1)=0

We get rid of parentheses

0x^2-1x-0x+0.1=0

We add all the numbers together, and all the variables

x^2-2x+0.1=0

a = 1; b = -2; c = +0.1;
Δ = b2-4ac
Δ = -22-4·1·0.1
Δ = 3.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{3.6}}{2*1}=\frac{2-\sqrt{3.6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{3.6}}{2*1}=\frac{2+\sqrt{3.6}}{2}
$