2x-3+2(7x+2)=-2(x+1)

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Solution for 2x-3+2(7x+2)=-2(x+1) equation: 



2x-3+2(7x+2)=-2(x+1)

We move all terms to the left:

2x-3+2(7x+2)-(-2(x+1))=0

We multiply parentheses

2x+14x-(-2(x+1))+4-3=0



We calculate terms in parentheses: -(-2(x+1)), so:

-2(x+1)

We multiply parentheses

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

16x-(-2x-2)+1=0

We get rid of parentheses

16x+2x+2+1=0

We add all the numbers together, and all the variables

18x+3=0

We move all terms containing x to the left, all other terms to the right

18x=-3

x=-3/18

x=-1/6

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