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3/x+3=2/x-5=16/(x+3)(x-5)
We move all terms to the left:
3/x+3-(2/x-5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-5)!=0We get rid of parentheses
x∈R
3/x-2/x+5+3=0
We multiply all the terms by the denominator
5*x+3*x+3-2=0
We add all the numbers together, and all the variables
8x+1=0
We move all terms containing x to the left, all other terms to the right
8x=-1
x=-1/8
x=-1/8
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