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((3x+7)/5)+((x+42)/6)=13
We move all terms to the left:
((3x+7)/5)+((x+42)/6)-(13)=0
We calculate fractions
(18x+42)/()+(5x+210)/()-13=0
We multiply all the terms by the denominator
(18x+42)+(5x+210)-13*()=0
We add all the numbers together, and all the variables
(18x+42)+(5x+210)=0
We get rid of parentheses
18x+5x+42+210=0
We add all the numbers together, and all the variables
23x+252=0
We move all terms containing x to the left, all other terms to the right
23x=-252
x=-252/23
x=-10+22/23
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