(2/3t)-(1/6)t=t-(13/2)

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Solution for (2/3t)-(1/6)t=t-(13/2) equation: 



(2/3t)-(1/6)t=t-(13/2)

We move all terms to the left:

(2/3t)-(1/6)t-(t-(13/2))=0



Domain of the equation: 3t)!=0

t!=0/1

t!=0

t∈R





Domain of the equation: 6)t!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+2/3t)-(+1/6)t-(t-(+13/2))=0

We multiply parentheses

-t^2+(+2/3t)-(t-(+13/2))=0

We get rid of parentheses

-t^2+2/3t-(t-(+13/2))=0

We calculate fractions


-t^2+()/6t^2+(-(t-(+13*3t)/6t^2=0

We add all the numbers together, and all the variables

-1t^2+()/6t^2+(-(t-(+13*3t)/6t^2=0

We multiply all the terms by the denominator


-1t^2*6t^2+(-(t-(+13*3t)+()=0



We calculate terms in parentheses: +(-(t-(+13*3t)+(), so:

-(t-(+13*3t)+(



Wy multiply elements

-6t^4+(-(t-(+13*3t)+()=0



We calculate terms in parentheses: +(-(t-(+13*3t)+(), so:

-(t-(+13*3t)+(



We do not support etpression: t^4

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