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12-2v=6(2+6v)-6v
We move all terms to the left:
12-2v-(6(2+6v)-6v)=0
We add all the numbers together, and all the variables
-2v-(6(6v+2)-6v)+12=0
We calculate terms in parentheses: -(6(6v+2)-6v), so:We get rid of parentheses
6(6v+2)-6v
We add all the numbers together, and all the variables
-6v+6(6v+2)
We multiply parentheses
-6v+36v+12
We add all the numbers together, and all the variables
30v+12
Back to the equation:
-(30v+12)
-2v-30v-12+12=0
We add all the numbers together, and all the variables
-32v=0
v=0/-32
v=0
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