3/5x+8=1/10x-40

Solution for 3/5x+8=1/10x-40 equation:

3/5x+8=1/10x-40

We move all terms to the left:

3/5x+8-(1/10x-40)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x-40)!=0

x∈R


We get rid of parentheses

3/5x-1/10x+40+8=0

We calculate fractions


30x/50x^2+(-5x)/50x^2+40+8=0

We add all the numbers together, and all the variables

30x/50x^2+(-5x)/50x^2+48=0

We multiply all the terms by the denominator


30x+(-5x)+48*50x^2=0

Wy multiply elements

2400x^2+30x+(-5x)=0

We get rid of parentheses

2400x^2+30x-5x=0

We add all the numbers together, and all the variables

2400x^2+25x=0

a = 2400; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·2400·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*2400}=\frac{-50}{4800}
=-1/96
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*2400}=\frac{0}{4800}
=0
$