2(2p-11)-2p+8=4(p-4)

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Solution for 2(2p-11)-2p+8=4(p-4) equation:



2(2p-11)-2p+8=4(p-4)
We move all terms to the left:
2(2p-11)-2p+8-(4(p-4))=0
We add all the numbers together, and all the variables
-2p+2(2p-11)-(4(p-4))+8=0
We multiply parentheses
-2p+4p-(4(p-4))-22+8=0
We calculate terms in parentheses: -(4(p-4)), so:
4(p-4)
We multiply parentheses
4p-16
Back to the equation:
-(4p-16)
We add all the numbers together, and all the variables
2p-(4p-16)-14=0
We get rid of parentheses
2p-4p+16-14=0
We add all the numbers together, and all the variables
-2p+2=0
We move all terms containing p to the left, all other terms to the right
-2p=-2
p=-2/-2
p=1

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