x2=x-2(x-2+x+2)

Solution for x2=x-2(x-2+x+2) equation:

x2=x-2(x-2+x+2)

We move all terms to the left:

x2-(x-2(x-2+x+2))=0

We add all the numbers together, and all the variables

x2-(x-2(+2x))=0

We add all the numbers together, and all the variables

x^2-(x-2(+2x))=0


We calculate terms in parentheses: -(x-2(+2x)), so:

x-2(+2x)

We multiply parentheses

x-4x

We add all the numbers together, and all the variables

-3x

Back to the equation:

-(-3x)


We get rid of parentheses

x^2+3x=0

a = 1; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·1·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*1}=\frac{-6}{2}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*1}=\frac{0}{2}
=0
$