14x+x2=225

Solution for 14x+x2=225 equation:

14x+x2=225

We move all terms to the left:

14x+x2-(225)=0

We add all the numbers together, and all the variables

x^2+14x-225=0

a = 1; b = 14; c = -225;
Δ = b2-4ac
Δ = 142-4·1·(-225)
Δ = 1096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1096}=\sqrt{4*274}=\sqrt{4}*\sqrt{274}=2\sqrt{274}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{274}}{2*1}=\frac{-14-2\sqrt{274}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{274}}{2*1}=\frac{-14+2\sqrt{274}}{2}
$