3/5(x+2)=2/3(x-3)

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Solution for 3/5(x+2)=2/3(x-3) equation: 



3/5(x+2)=2/3(x-3)

We move all terms to the left:

3/5(x+2)-(2/3(x-3))=0



Domain of the equation: 5(x+2)!=0

x∈R





Domain of the equation: 3(x-3))!=0

x∈R



We calculate fractions


(9xx/(5(x+2)*3(x-3)))+(-10xx/(5(x+2)*3(x-3)))=0



We calculate terms in parentheses: +(9xx/(5(x+2)*3(x-3))), so:

9xx/(5(x+2)*3(x-3))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)





We calculate terms in parentheses: +(-10xx/(5(x+2)*3(x-3))), so:

-10xx/(5(x+2)*3(x-3))

We multiply all the terms by the denominator


-10xx

Back to the equation:

+(-10xx)



We get rid of parentheses

9xx-10xx=0

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