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X-4(X-7)+10=3X+2(X-1)
We move all terms to the left:
X-4(X-7)+10-(3X+2(X-1))=0
We multiply parentheses
X-4X-(3X+2(X-1))+28+10=0
We calculate terms in parentheses: -(3X+2(X-1)), so:We add all the numbers together, and all the variables
3X+2(X-1)
We multiply parentheses
3X+2X-2
We add all the numbers together, and all the variables
5X-2
Back to the equation:
-(5X-2)
-3X-(5X-2)+38=0
We get rid of parentheses
-3X-5X+2+38=0
We add all the numbers together, and all the variables
-8X+40=0
We move all terms containing X to the left, all other terms to the right
-8X=-40
X=-40/-8
X=+5
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