17x2+48x=9

Solution for 17x2+48x=9 equation:

17x^2+48x=9

We move all terms to the left:

17x^2+48x-(9)=0

a = 17; b = 48; c = -9;
Δ = b2-4ac
Δ = 482-4·17·(-9)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-54}{2*17}=\frac{-102}{34}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+54}{2*17}=\frac{6}{34}
=3/17
$