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3/4x-6=x-8
We move all terms to the left:
3/4x-6-(x-8)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
3/4x-x+8-6=0
We multiply all the terms by the denominator
-x*4x+8*4x-6*4x+3=0
Wy multiply elements
-4x^2+32x-24x+3=0
We add all the numbers together, and all the variables
-4x^2+8x+3=0
a = -4; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·(-4)·3
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{7}}{2*-4}=\frac{-8-4\sqrt{7}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{7}}{2*-4}=\frac{-8+4\sqrt{7}}{-8} $
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