4(z-48)+1z=-(48-z)

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Solution for 4(z-48)+1z=-(48-z) equation: 



4(z-48)+1z=-(48-z)

We move all terms to the left:

4(z-48)+1z-(-(48-z))=0

We add all the numbers together, and all the variables

4(z-48)+1z-(-(-1z+48))=0

We add all the numbers together, and all the variables

z+4(z-48)-(-(-1z+48))=0

We multiply parentheses

z+4z-(-(-1z+48))-192=0



We calculate terms in parentheses: -(-(-1z+48)), so:

-(-1z+48)

We get rid of parentheses

1z-48

We add all the numbers together, and all the variables

z-48

Back to the equation:

-(z-48)



We add all the numbers together, and all the variables

5z-(z-48)-192=0

We get rid of parentheses

5z-z+48-192=0

We add all the numbers together, and all the variables

4z-144=0

We move all terms containing z to the left, all other terms to the right

4z=144

z=144/4

z=36

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