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7z^2+91z=0
a = 7; b = 91; c = 0;
Δ = b2-4ac
Δ = 912-4·7·0
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8281}=91$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-91}{2*7}=\frac{-182}{14} =-13 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+91}{2*7}=\frac{0}{14} =0 $
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